When placed near a second charge, a 60-μC charge experiences a force of 0.30 N. What is the electric field strength at the location of the 60-μC charge? What is the strength of the electric field at the location of the test charge?

Answer :

Answer:

[tex]E=5000N/C[/tex]

Step-by-step explanation:

From the question we are told that

Charge [tex]q= 60 \mu C[/tex]

Force [tex]F_=0.30N[/tex]

Generally the equation for electric field strength is mathematically given as

[tex]E=F/q[/tex]

[tex]E=\frac{0.30}{60*10^-^6}[/tex]

Therefore

[tex]E=5000N/C[/tex]

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