Answer :
Answer:
v₂ = 2,665 m / s
Explanation:
This is an exercise of conservation of the momentum, we define a system formed by the two cars, so that the forces during the collision are internal and the moment is conserved.
Initial instant. Before the crash
p₀ = m v_o
Final moment. Right after the crash
p_f = m v₁ + M v₂
where the first car uses subscript 1 and has a mass m = 1 kg and the second car uses the subscript 2 with a mass M = 2kg
how the moment is preserved
p₀ = p_f
m v_o = m v₁ + M v₂
They indicate that the collision is elastic, therefore the kinetic energy is conserved, the velocity of the first car is v1 = -1.33 me / S
v₂ = [tex]\frac{ m ( v_o - v_1)}{M}[/tex]
we calculate
v₂ = [tex]\frac{ 1 ( 4 + 1.33)}{2}[/tex]
v₂ = 2,665 m / s