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A sea lion swims in still water at the speed of 15 km/h. While hunting for fish, it swims with the current for 35 km and against the same current for 25 km. The sea lion swims with the current for the same amount of time it swims against the current. What is the speed of the current?

Answer :

Answer:

x = 5/2 km/h

Step-by-step explanation:

Lets x be the speed of the current

The sea lion's speed with the current: 15 + x

The sea lion's speed against the current: 15 - x

Total distance in km with the current: 35

Total distance in km against the current: 25

Time with the current: 35/(15 + x)

Time against the current: 25/(15 - x)

So we do...

35/(15 + x) - 25/(15 - x) = 0

35(15 - x)/(15 + x) - 25(15 + x)/(15 - x): Having common denominators which is (15 + x)(15 - x)

525 - 35x - 375 - 25x = 0: Mutipling the (15 + x)(15 - x)to 0 getting 0

150 - 60x = 0

30(5 - 2x) = 0

x = 5/2

abidemiokin

The speed of the current is 2.5 km/hr

Speed and Distances

From the given information

Lets x be the speed of the current

  • The sea lion's speed with the current will be 15 + x
  • The sea lion's speed against the current will be 15 - x

Also, we have that;

Total distance in km with the current to be 35 while the total distance in km against the current is 25

mathematically;

Time with the current = 35/(15 + x)

Time against the current =  25/(15 - x)

Equating both expression to get the value of "x

35/(15 + x) = 25/(15 - x) = 0

35/(15 + x) - 25/(15 - x) = 0

35(15 - x)/(15 + x) - 25(15 + x)/(15 - x)

Mutiplying the (15 + x)(15 - x)to have:

150 - 60x = 0

30(5 - 2x) = 0

x = 5/2

x = 2.5

Hence the speed of the current is 2.5 km/hr

Learn more on speed and distance here: https://brainly.com/question/4931057

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