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8x-5y=-118x−5y=−118, x, minus, 5, y, equals, minus, 11 xxx-intercept: \Big((left parenthesis ,,comma \Big))right parenthesis yyy-intercept: \Big((left parenthesis

Answer :

Given:

The equation is

[tex]8x-5y=-11[/tex]

To find:

The x-intercept and y-intercept of the given equation.

Solution:

We have,

[tex]8x-5y=-11[/tex]

For x-intercept, y=0.

[tex]8x-5(0)=-11[/tex]

[tex]8x=-11[/tex]

[tex]x=-\dfrac{11}{8}[/tex]

[tex]x=-1.375[/tex]

So, the x-intercept is at point (-1.375,0).

For y-intercept, x=0.

[tex]8(0)-5y=-11[/tex]

[tex]-5y=-11[/tex]

[tex]y=\dfrac{-11}{-5}[/tex]

[tex]y=2.2[/tex]

So, the y-intercept is at point (0,2.2).

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