Answer :
the answer is 3x^2-12=-12, imiplies 3x^2 = - 12 + 12 = 0
so 3x^2 = 0 implies x = 0
there is one solution, x =0
so 3x^2 = 0 implies x = 0
there is one solution, x =0
Answer:
The given function is :
3 x² - 12 = -12
Adding 12 to both L HS and R HS
3 x²- 12 +12= -12 + 12
3 x²=0
x²=0
x=0
without Solving Graphically, got a single solution, x=0,which satisfies the above function.
Now,checking Graphically, as this is quadratic function ,number of times it crosses the X axis ,are solution of this Quadratic Function.
The function crosses , the X axis just once,
So,there is unique Solution, which is, x=0.
None of the option is true.
