julissagarcia1114 julissagarcia1114

Today at 7:05 PM
Chemistry

Answered

Consider this reaction mechanism:
Step 1: C4H9Br C4H9+ + Br- (slow)
Step 2: C4H9+ + OH- C4H9OH (fast)
Which rate law is consistent with the mechanism?

Consider this reaction mechanism: Step 1: C4H9Br C4H9+ + Br- (slow) Step 2: C4H9+ + OH- C4H9OH (fast) Which rate law is consistent with the mechanism? class=

Answer :

21ahmedfa 21ahmedfa

Today at 7:09 PM

C. rate = k[C4H9Br]

The slow step is always the rate-determining step. In the slow step, C4H9Br is the only reactant and has a coefficient of 1, so it is first order in the rate law.

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