Ampere's law allows us to find the result of which statement is correct about the magnetic field is:
A) Doubling the number of times the wire wraps around the nail.
Ampere's law states that the magnetic field in a closed path is equal to the current on the path.
B. s = μ₀ I
where B is the magnetic field, s the path, I the current and μ₀ the permittivity of the vacuum.
In this case the wound wire forms a closed path and the wire assembly is called a solenoid, Ampere's law for N turn is
B l = N μ₀ I
B = [tex]\mu_o \frac{N}{l} I[/tex]
If we change the vacuum or air for a material the permittivity changes, in the table are some tabulated values.
Material permittivity ( T m/A)
vacuum μ₀ = 4π 10⁻⁷
air 1,0006 μ₀
mica 3μ₀
PCV 30μ₀
iron 5000μ₀
We must change the permittivity of the vacuum changes by the permittivity of the material in the expression.
Ohm's law states that the potential difference in a circuit is equal to the product of current and resistance.
V = I R
[tex]I= \frac{V}{R}[/tex]I = V / R
Let's replace.
[tex]B = \mu \frac{N}{l}\ \frac{V}{R}[/tex]B = mu N / L V / R
With this expression let us examine the different statements.
A) True. Increasing the number of turns increases the magnetic field produced.
B) False. When the potential difference decreases, the magnetic field decreases.
D) False. From the table we see that the magnetic permittivity of plastic is much lower than that of iron, therefore the magnetic field decreases.
In conclusion, using Ampere's law we can find the result of which statement is correct about the magnetic field is:
A) Doubling the number of times the wire wraps around the nail.
Learn more about magnetic fields here: brainly.com/question/7802337