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What is the slope of a line perpendicular to the line whose equation is 4x−10y=404x−10y=40. Fully simplify your answer.

Answer :

Leora03

Answer:

[tex] - \frac{5}{2} [/tex]

Step-by-step explanation:

4x -10y= 40

Let's rewrite this equation in the slope-intercept form (y= mx +c) so that we can obtain it's slope.

10y= 4x -40

Divide both side by 10:

[tex]y = \frac{2}{5} x - 4[/tex]

The product of the gradients of perpendicular lines is -1.

⅖(gradient of line)= -1

Gradient of perpendicular line

[tex] = - 1 \div \frac{2}{5} [/tex]

[tex] = - 1 \times \frac{5}{2} [/tex]

[tex] = - \frac{5}{2} [/tex]

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