Answer :
gravity pulls at 32 feet per second so it would take .75sec to hit the ground now make an equation that can make this applicable so after .75 second T it would be at 0 feet H
Answer:
[tex]h=16t^2[/tex]
Step-by-step explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32 ft/s²
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow h=ut+\frac{1}{2}32\times t^2\\\Rightarrow h=ut+16t^2[/tex]
Here, u = 0 so,
[tex]h=0t+16t^2\\\Rightarrow h=16t^2[/tex]
The equation is [tex]h=16t^2[/tex]
[tex]24=16t^2\\\Rightarrow t=\sqrt{\frac{24}{16}}\\\Rightarrow t=1.22\ s[/tex]
Time taken by the ball to hit the ground is 1.22 seconds