Answer:
Yes, Its center at (5,4) and a radius of 4 units. Does the point (9,0) lie on the circumference of circle F.
Answer:
no
Step-by-step explanation:
Calculate the distance d between the centre and the given point.
If the distance between the points is 4 then it lies on the circle.
Using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (9, 0 )
d = [tex]\sqrt{(9-5)^2+(0-4)^2}[/tex]
= [tex]\sqrt{4^2+(-4)^2}[/tex]
= [tex]\sqrt{16+16}[/tex]
= [tex]\sqrt{32}[/tex]
= 4[tex]\sqrt{2}[/tex] ≠ 4
Since 4[tex]\sqrt{2}[/tex] > 4 then (0, 9) lies outside the circle, not on the circumference
