Answered

Francine bought a TV that is 31 inches tall and 57 inches wide. She is going to mount it on the wall in her living room. The wall is 8 feet wide and 9 feet tall.

How many square inches of the wall will not be covered by the TV once it is mounted?

Answer :

100003573

Answer:

the tv would actually be too big for the wall, or cover all of that wall and then some.

Step-by-step explanation:

so the formula for this is going to be lxw

notice the units are different. this is an easy fix. either divide the inches by 12 or multiply the ft by 12. (12 inches in a foot)

tv=  31in x 57in= 1,767 in2

wall=  8ftx9ft= 72 ft2

if the wall is 72ft2, then it would be 864in2

(72in2 x 12= 864in2)

if the tv is 1,767 in2 and the wall is  864in2 ; the tv would actually be too big for the wall; or cover all of that wall and then some.

rococo908

Answer:

8,601 square inches

Step-by-step explanation:

First, convert the dimensions of the wall from feet to inches.

There are 12 inches in 1 foot, so multiply the number of feet by 12.

8(12) = 96

9(12) = 108

Find the area of the wall in square inches, using the formula A = lw

A = lw

A = 108(96)

A = 10368

Find the area of the TV using the same formula:

A = lw

A = 31(57)

A = 1767

Subtract the area of the TV from the area of the wall:

10368 - 1767

= 8601

So, 8,601 square inches of the wall will not be covered by the TV

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