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(04.02 MC)
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What is the y-intercept of the line perpendicular to the line y = x + 1 that includes the point (4, 1)?

Answer :

xero099

Answer:

The intercept of the line perpendicular to the line [tex]y = x + 1[/tex] is 5.

Step-by-step explanation:

The line [tex]y = x + 1[/tex] has a slope 1. By Analytic Geometry, the slope of the line perpendicular to the original line is determine by the following formula:

[tex]m_{\perp} = -\frac{1}{m}[/tex] (1)

Where:

[tex]m[/tex] - Slope of the original line.

[tex]m_{\perp}[/tex] - Slope of the line perpendicular to the original line.

If we know that [tex]m = 1[/tex], then the new slope is:

[tex]m_{\perp} = -\frac{1}{1}[/tex]

[tex]m_{\perp} = -1[/tex]

A line is defined by the following expression:

[tex]y = m\cdot x + b[/tex] (2)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]m[/tex] - Slope.

[tex]b[/tex] - Intercept.

If we know that [tex](x,y) = (4,1)[/tex] and [tex]m = -1[/tex], then the intercept of the line perpendicular to the original line:

[tex]b = y - m\cdot x[/tex]

[tex]b = 1+4[/tex]

[tex]b = 5[/tex]

The intercept of the line perpendicular to the line [tex]y = x + 1[/tex] is 5.

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