FIND THE CENTER AND THE RADIUS OF THIS EQUATION: (X+4)^2+ (Y-3)^2 =16

Answer:
centre = (-4,3) and radius 4
Step-by-step explanation:
Standard equation for a circle :
(x-a)² + (y-b)² = r²
for a circle with radius r centred at (a,b).
(X+4)^2+ (Y-3)^2 =16
(x - (-4))² + (y-3)² = 4²
Therefore centre (a,b) = (-4,3) and radius 4