A line contains the piont (4,5) and is perpendicular to a line with a slope of -2/3. Write an equarion of the line satisfying the given conditions. Write the answer in slope-intercept form

Answer :

Answer:

[tex]y=\frac{3}{2}x-3.5[/tex] or, preferably, [tex]y=\frac{3}{2}x-\frac{7}{2}[/tex]

Step-by-step explanation:

First is to find the perpendicular slope. In this case, you swap the numerator and denominator and then multiply that fraction by -1.

In this case, -2/3's inverse slope is 3/2.

Now, the initial y=3/2 passes through 7.5,5

So, you must subtract 3.5 from that to make it pass through 4,5.

In this way, you get the answer in slope-intercept form.

Answer:

y = [tex]\frac{3}{2}[/tex] x - 1

Step-by-step explanation:

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{2}{3} }[/tex] = [tex]\frac{3}{2}[/tex] , then

y = [tex]\frac{3}{2}[/tex] + c ← partial equation in slope- intercept form

To find c substitute (4, 5) into the partial equation

5 = 6 + c ⇒ c = 5 - 6 = - 1

y = [tex]\frac{3}{2}[/tex] x - 1 ← equation of line

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