Answer :
Answer:
- Center = (3, 0)
- Radius = 3
- Graph = see below
Concept:
Here, we need to know the idea of the circle equation.
Circle equation: (x - h)² + (y - k)² = r²
(h, k) = center
r = radius
x = variable
y = variable
Solve:
Given expression
(x - 3)² + y² = 9
Find the point of the center
(h, k) = [tex]\boxed{(3,0)}[/tex]
Find the length of the radius
r² = 9
[tex]\boxed{r=3}[/tex]
Hope this helps!! :)
Please let me know if you have any questions

(x-3)²+y²=9
(x-3)²+(y-0)²=3²
The equation can be written in the form (x-p)²+(y-q)²=r², so it represents a circle with the radius r=3 and the center (3, 0)
Hope my answer helped u :)
(x-3)²+(y-0)²=3²
The equation can be written in the form (x-p)²+(y-q)²=r², so it represents a circle with the radius r=3 and the center (3, 0)
Hope my answer helped u :)
