Answer :
Answer:
(2x-4) (x+5)=0
2x(x+5) -4(x+5)=0
2x^2+10x-4x-20=0
2x^2+6x-20=0
x^2+3x-10=0 ( Taking common of 2 )
x^2+(5-2)x-10=0 • (3=(5-2)x)
x^2+5x-2x-10=0
x(x+5)-2(x-5) =0 • Taking common
(x+5)(x-2) =0
so x=-5 or x=2.
Answer:
(2x-4) (x+5)=0
2x(x+5) -4(x+5)=0
2x^2+10x-4x-20=0
2x^2+6x-20=0
x^2+3x-10=0 ( Taking common of 2 )
x^2+(5-2)x-10=0 • (3=(5-2)x)
x^2+5x-2x-10=0
x(x+5)-2(x-5) =0 • Taking common
(x+5)(x-2) =0
so x=-5 or x=2.