Answer :

discipulus

Answer:

[tex]y = mx + c \\ - 3 = 2m + c \\ - 2 = 4m + c \\ subtract \: (2) - (1) \\ 1 = 2m \\ m = \frac{1}{2} \\ - 3 = 2( \frac{1}{2} ) + c \\ c = - 4 \\ y = \frac{1}{2}x - 4 [/tex]

alternative method

[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]

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