The m2 TQR is decreased by equal increments as shown in the series of figures
below.
Susan was asked to make predictions about Figure 4. Susan predicts that PR will be
parallel to TQ. Which statement best supports Susan's prediction?

The m2 TQR is decreased by equal increments as shown in the series of figures below. Susan was asked to make predictions about Figure 4. Susan predicts that PR class=

Answer :

The angle formed at corresponding locations between lines  [tex]\overline{PR}[/tex] and [tex]\overline {TQ}[/tex]

and the common transversal [tex]\overline {WV}[/tex] are corresponding angles.

The statements that support Susan's predictions are;

  • m∠PRV and m∠TQR are corresponding angles
  • m∠PRV = 130° = m∠TQR
  • m∠PRV ≅ m∠TQR by congruency definition
  • [tex]\overline{PR} \cong \overline {TQ}[/tex] by corresponding angles theorem

Reason:

The given measures of ∠TQR are;

In figure 1, m∠TQR = 145°

In figure 2, m∠TQR = 140°

In figure 3, m∠TQR = 135°

Therefore, we have the following sequence;

145°, 140°, 135°

From the above sequence, we have that each subsequent term, is less

than the previous one by 5 degrees, therefore on figure 4, we have;

Figure 4, m∠TQR = 135° - 5° = 130°

Therefore, on figure 4, we get;

m∠PRV and m∠TQR are corresponding angles

m∠PRV = 130° = m∠TQR

Which gives;

m∠PRV ≅ m∠TQR by definition of congruency

Therefore;

[tex]\overline{PR} \cong \overline {TQ}[/tex] by corresponding angles theorem.

Corresponding angles theorem states that if two lines that are parallel have

a common transversal cutting both lines, the corresponding angles formed

are congruent.

Therefore, the statements that support Susan's prediction are;

On figure 4;

  • m∠PRV and m∠TQR are corresponding angles
  • m∠PRV = 130° = m∠TQR
  • m∠PRV ≅ m∠TQR by definition
  • [tex]\overline{PR} \cong \overline {TQ}[/tex] by corresponding angles theorem

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