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Consider the reaction:

BaCl2 + K2CrO4 ---> BaCrO4 + KCl



How many grams of barium chromate can be obtained from 75.0 mL of 0.150 M BaCl2 solution? (hint: balance equation 1st)

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yashjaglan012

Answer:

2.84g is the answer

Step-by-step explanation:

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