Answer :
The average atomic mass of element X that has two isotopes (one of 45.0 amu mass and 45% abundance and the other of 47.0 amu mass and 55.0% abundance) is 46.1 amu (option 1).
The average atomic mass (A) of element X can be calculated as follows:
[tex] A = m_{1}\%_{1} + m_{1}\%_{1} [/tex] (1)
Where:
m₁: is the mass of isotope 1 = 45.0 amu
m₂: is the mass of isotope 2 = 47.0 amu
%₁: is the abundance percent of isotope 1 = 45.0 %
%₂: is the abundance percent of isotope 1 = 55.0 %
Hence, the average atomic mass is (eq 1):
[tex] A = m_{1}\%_{1} + m_{1}\%_{1} = 45.0 amu*45.0\% + 47.0 amu*55.0\% = 45.0 amu*0.45 + 47.0 amu*0.55 = 46.1 amu [/tex]
Therefore, the average atomic mass of element X is 46.1 amu (option 1).
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I hope it helps you!
