Answer :
Answer:
k^-1(x) = -1/128+16x
Domain = ]-infinity,-8[ U ]-8,infinity[
Range = ]-infinity,0[ U ]0,infinity[
Step-by-step explanation:
k(x) = -1/16x = -8
y = -1/16x = -8
x = -1/16y = -8
y = -1/128+16x
k^-1(x) = -1/128+16x
Answer:
k^-1(x) = -1/128+16x
Domain = ]-infinity,-8[ U ]-8,infinity[
Range = ]-infinity,0[ U ]0,infinity[
Step-by-step explanation:
k(x) = -1/16x = -8
y = -1/16x = -8
x = -1/16y = -8
y = -1/128+16x
k^-1(x) = -1/128+16x