Answer :
given :- tanA=4/3
we already know that tanA=P/B
From Pythagorean theorem we get..
H²=P²+B²
H²=4²+3²
H²=16+9
H²=25
H²=5²
H=5
SinA=P/H
CosA=B/H
from that
SinA= 4/5
CosA=3/5
given :- tanA=4/3
we already know that tanA=P/B
From Pythagorean theorem we get..
H²=P²+B²
H²=4²+3²
H²=16+9
H²=25
H²=5²
H=5
SinA=P/H
CosA=B/H
from that
SinA= 4/5
CosA=3/5