Answer :
9514 1404 393
Answer:
lock code: 3709528614
Step-by-step explanation:
Given:
- 3F = D
- H×K = B
- J+A = CC
- H×2 = B
- H×F = CK
- D×F = KG
- G +B +E =D +A+C
- H×A = KE
- K×F = J
Find:
single digit corresponding to each letter
Solution:
CC must be 11, because the sum of any pair of single digits cannot exceed 18. (C = 1).
K must be 2, because H×K = B = H×2. (K = 2)
The only single-digit products involving 3 are 3×1 = 3, 3×2 = 6, and 3×3 = 9. We know F is not 1 or 2, so for 3F = D we must have F = 3, D = 9. (F = 3)(D = 9)
CK = 12, so H×F = 3H = 12. This means H = 4. (H = 4)
2H = B, so B = 8. (B = 8)
D×F = KG. Using the values for D, F, K, we find 9×3 = 27. (G = 7)
K×F = J = 2×3. (J = 6)
At this point, the only unassigned digits are 0 and 5.
H×A = KE. Filling in known values, this is 4A = 20 +E. (A = 5)(E = 0)
The sum E+15 = A+10 can also be used to assign values to A and E.
__
Then the letters corresponding to the digits 0-9 are ...
[tex]\texttt{01234 56789}\\\texttt{ECKFH AJGBD}[/tex]
The bicycle lock code is 3709528614.