Answer :
With the use of formula, the time of flight, the horizontal displacement, and the peak height of the football are 1.8s, 63.6 m, 15.8 m
PROJECTILE
The object that is been projected to take a trajectory path is known as Projectile.
Given that a football is kicked with an initial velocity of 25 m/s at an angle of 45-degrees with the horizontal.
a. The time of flight can be calculated by using the formula below
t = usinФ / g
Where
u = initial velocity = 25 m/s
Ф = 45 degrees
Substitute all the parameters into the formula
t = (25 x sin 45) / 9.8
t = 17.678 / 9.8
t = 1.8 s
b. The horizontal displacement R, will be
R = ucosФT
Where T = 2t = 2 x 1.8 = 3.6s
R = 25cos45 x 3.6
R = 63.64 m
c. The peak height of the football.
At maximum height, V = 0
H = [tex]U^{2}[/tex][tex]Sin^{2}[/tex]Ф / 2g
H = [tex]25^{2}[/tex] [tex](Sin45)^{2}[/tex] / (2 x 9.8)
H = 312.5 / 19.8
H = 15.78 m
Therefore, the time of flight, the horizontal displacement, and the peak height of the football are 1.8s, 63.6 m, 15.8 m approximately.
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