trashyxpoet
Answered

you can approximate e by substituting large values for n into the expression ______.

a) (1-n)^1/n
b) (1+1/n)^n
c) (1-1/n)^n
d) (1+n)^1/n

Answer :

e is approximately equal to (1+ 1/n) ^n

You can test this:

(1 + (1/50000))^50000 = 2.718

So the answer is B
APEanswerOnLy124354

Answer:

b) (1+1/n)^n

Step-by-step explanation:

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