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In proton beam therapy, a beam of high-energy protons is used to kill cancerous cells in a tumor. In one system, the beam, which consists of protons with an energy of 2.8×10−11J, has a current of 84 nA. The protons in the beam mostly come to rest within the tumor. The radiologist has ordered a total dose corresponding to 3.4×10−3J of energy to be deposited in the tumor.

Answer :

Lanuel

The number of protons that strike the tumor each second is [tex]1.75 \times 10^8[/tex] protons.

Given the following data:

  • Energy of proton = [tex]2.8 \times 10^{-11}[/tex] Joules.
  • Current = 84 nA to A = [tex]84 \times 10^{-9}[/tex] Ampere.
  • Energy of total dose = [tex]3.4 \times 10^{-3}[/tex] Joules.

Scientific data:

  • Charge of proton = [tex]1.602 \times 10^{-19}[/tex] C.

To determine the number of protons that strike the tumor each second:

How to determine the number of protons.

Mathematically, the quantity of charge per unit time is given by this formula:

[tex]Q =It=Ne\\\\N = \frac{Q}{e}[/tex]

Where:

  • N is the number of protons.
  • t is the time measured in seconds.
  • I is the current.
  • e is the charge of protons.

Substituting the parameters into the formula, we have;

[tex]N=\frac{2.8 \times 10^{-11} }{1.602 \times 10^{-19}} \\\\N = 1.75 \times 10^{8}[/tex]protons.

Read more on charges here: brainly.com/question/14372859

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