Answer :
Step-by-step explanation:
[tex]4\cdot \:11-x+4=33[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:4\cdot \:11=44[/tex]
[tex]44-x+4=33[/tex]
[tex]\mathrm{Group\:like\:terms}[/tex]
[tex]-x+44+4=33[/tex]
[tex]\mathrm{Add\:the\:numbers:}\:44+4=48[/tex]
[tex]-x+48=33[/tex]
[tex]\mathrm{Subtract\:}48\mathrm{\:from\:both\:sides}[/tex]
[tex]-x+48-48=33-48[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]-x=-15[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}-1[/tex]
[tex]\frac{-x}{-1}=\frac{-15}{-1}[/tex]
[tex]Simplify[/tex]
[tex]x=15[/tex]
Answer:
Okay so yes the answer is 15
Step-by-step explanation:
It begins with 4X11 which is 44
So the equation becomes 44-x+4=33
Then I add 44 plus 4 which is me adding all the available terms which is 48
Then I subtracted 33 from 48 to find the value of x
And 48-33=15
So there you pretty much have it.
To be sure you can plug the answer in.
4x11=44
44-(x) which is 15 so 44-15=29
29+4=33
There ya have it!