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A luge run is straight for the first 10 m. If the velocity of the luger when he passes the start line is +25 m/s and his acceleration is constant at +9.5 m/s2, about how fast is he going when he hits the first turn?

Answer :

V^2 =U^2 +2AS
V^2 = 25 ^2 + 2x9.5x10
V^2 = 625 + 1900 = 2525
V = 50.25

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