Answer :
Hello my friend,
We want to find the value = b^2 - 4ac
We have :
5x^2 +7x = 6
Subtract ''6" for the side light from equacion.
Then stay:
5x^2 +7x - 6 = 0
Uau, Look now!
Like look with the equacion = ax^2+bx+c
Where ,
a = 5
b = 7
c = -6
As we know,
Delta = b^2 -4ac
Then,
Delta = 7^2 -4.5.(-6)
Delta = 49 -20.(-6)
Delta = 49 + 120
Delta = 169
This is tha answer...
I hope that help...
We want to find the value = b^2 - 4ac
We have :
5x^2 +7x = 6
Subtract ''6" for the side light from equacion.
Then stay:
5x^2 +7x - 6 = 0
Uau, Look now!
Like look with the equacion = ax^2+bx+c
Where ,
a = 5
b = 7
c = -6
As we know,
Delta = b^2 -4ac
Then,
Delta = 7^2 -4.5.(-6)
Delta = 49 -20.(-6)
Delta = 49 + 120
Delta = 169
This is tha answer...
I hope that help...