Answer :
Answer:
The Direct variation says that:
[tex]y \propto x[/tex]
then; the equation is in the form of y =kx where k is the constant of variation.
As per the statement:
One yard is approximately 0.91 meter.
⇒1 yard = 0.91 m
by definition of proportion:
[tex]\frac{x}{y} = \frac{1}{0.91}[/tex]
By Cross multiply we get;
[tex]0.91x = y[/tex]
Therefore, the direct variation equation that relates x yards to y meters is: y=0.91x
In the direct general equation one variable is constant times of the other variable. The direct variation equation that relates [tex]x[/tex] yards to [tex]y[/tex] meters is [tex]y=0.91x[/tex].
The direct general equation has to be find out.
What is direct general equation?
The direct general equation is the equation which represent the relationship between the two variables.
In the direct general equation one variable is constant times of the other variable.The general form of the direct general equation is,
[tex]y=kx[/tex]
Here, [tex]x,y[/tex] is the variable and [tex]k[/tex] is the constant.
Given information-
One yard is equal to the 0.91 meters (approximately).
The variable [tex]x[/tex] represents the yards.
The variable [tex]y[/tex] represents the meters.
As one yard is approximately equal to the 0.91 meters, and variable [tex]x[/tex] and [tex]y[/tex] represents the yards and meters respectively.
Thus the variable [tex]y[/tex] is 0.91 times to the variable [tex]x[/tex]. therefore,
[tex]y=0.91x[/tex]
This is the required equation.
Hence the direct variation equation that relates [tex]x[/tex] yards to [tex]y[/tex] meters is [tex]y=0.91x[/tex].
Learn more about the direct variation equation here;
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