6 blue chips 13 pink chips 7 white chips Vicky takes out a chip from the bag randomly without looking. She replaces the chip and then takes out another chip from the bag. What is the probability that Vicky takes out a blue chip in both draws? PLEASE HELLPP

Answer :

mhanifa

Answer:

  • 9/169

Step-by-step explanation:

Total number of chips

  • 6 + 13 + 7 = 26

Probability of a blue chip

  • P(blue) = blue / total = 6 / 26 = 3/13

The subsequent blue has same probability as the chip is replaced.

Probability of two blue chips is

  • P(blue, blue) = 3/13*3/13 = 9/169
semsee45

Answer:

[tex]\sf \dfrac{9}{169}[/tex]

Step-by-step explanation:

The bag has:

  • 6 blue chips
  • 13 pink chips
  • 7 white chips

⇒ Total number of chips = 6 + 13 + 7 = 26

Probability Formula

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

Probability of choosing a blue chip from the first draw:

[tex]\implies \sf P(Blue)=\dfrac{6}{26}[/tex]

As the chips are replaced, the probability of choosing a blue chip from the second draw is the same as the first.

Therefore, the probability of taking out a blue chip in both draws is:

[tex]\begin{aligned}\implies \sf P(Blue)\:and\:P(Blue) & = \sf \dfrac{6}{26} \times \dfrac{6}{26}\\\\& = \sf \dfrac{6 \times 6}{\26 \times 26}\\\\& = \sf \dfrac{36}{676}\\\\& = \sf \dfrac{36 \div 4}{676 \div 4}\\\\& = \sf \dfrac{9}{169}\end{aligned}[/tex]

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