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The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by the equation t = 35 cosine (startfraction pi over 6 endfraction (m 3) 55, where m = 0 represents january 1, m = 1 represents february 1, m = 2 represents march 1, and so on. which equation also models this situation? t = negative 35 sine (startfraction pi over 6 endfraction m) 55 t = negative 35 sine (startfraction pi over 6 endfraction (m 3)) 55 t = 35 sine (startfraction pi over 6 endfraction m) 55 t = 35 sine (startfraction pi over 6 endfraction (m 3)) 55

Answer :

The answer will be t=-35Sin{[tex]\pi[/tex]/6m)+55 average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

What is temperature?

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

For the equation: 35cos(pi/6(m+3)+55)

Simplify it by multiplying pi/6 in the bracket values:  

[tex]=35 Cos (\dfrac{\pi m}{6}+\dfrac{3\pi }{6}+55)[/tex]

[tex]=35 Cos(\dfrac{\pi m}{6}+55+\dfrac{\pi}{2})[/tex]

Now suppose x = m.pi/6+55, while pi/2 = 90⁰

As per law cos(x+90⁰)=-sin(x)

so,cos((m.pi/6)+55+90⁰=-sin((m.pi/6)+55)

Hence answer will be

[tex]=-35Sin(\dfrac{\pi m}{6}+55)[/tex]

The law cos(x+90⁰)=-sin(x) can be proved by putting y=90⁰ in the following formula,

cos(x+y)=cos(x).cos(y)-sin(x).sin(y)

Hence the answer will be t=-35Sin{[tex]\pi[/tex]/6m)+55 average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

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Answer:

A

Step-by-step explanation:

t = negative 35 sine (StartFraction pi Over 6 EndFraction m) + 55

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