Answer :
The generator power will be 59 kW. Power drop is the main factor for finding the generated power.
What is the power rating?
The maximum power input allowed to pass through a piece of equipment is known as the equipment's power rating.
Power drop = 5%
The relation of the frequency change with the power drop is;
[tex]\rm \frac{df}{dp} =5\%\\\\ \frac{f_{rated-f_1}}{P_{rated}-P_1}=0.05\\\\ \frac{f_{rated-60}}{100-61}=0.05\\\\ f_{rated}=61.95[/tex]
For the grid frequency, 59.9 Hz
[tex]\rm \frac{f_{rated-f_2}}{P_{rated}-P_2}=0.05[/tex]
[tex]\rm \frac{61.95-f_2}}{100-P_2} =0.05\\\\ 100-P_2 =20(61.95-59.9)\\\\P_2=100-41 \\\\ P_2=59 \ kW[/tex]
Hence, the generator power will be 59 kW.
To learn more about the power rating, refer to the link;
https://brainly.com/question/13787703
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