Answer:
[tex]64^{\circ}[/tex]
Step-by-step explanation:
[tex]~~~~~~\cos \angle E = \sin \angle F\\\\\implies \cos 26^{\circ} = \sin \angle F\\ \\\implies \angle F = \sin^{-1} \left( \cos 26^{\circ} \right)\\\\\implies \angle F = \sin^{-1} \left(\sin(90^{\circ}-26^{\circ}) \right)\\\\\implies \angle F = \sin^{-1} \left( \sin 64^{\circ} \right)\\\\\implies \angle F = 64^{\circ}[/tex]
