Answer :
[tex]\mathbf u\cdot\mathbf v=\|\mathbf u\|\|\mathbf v\|\cos\theta[/tex]
where [tex]\theta[/tex] is the angle between the vectors. You have
[tex]10\times9+6\times5=\sqrt{10^2+6^2}\sqrt{9^2+5^2}\cos\theta\iff \cos\theta=\dfrac{30}{\sqrt{901}}\implies \theta\approx1.909^\circ[/tex]
The vectors would be orthogonal if the dot product had been zero, but that's clearly not the case.
They would be parallel if the angle turned out to be [tex]0^\circ[/tex] or [tex]180^\circ[/tex], but that's also not the case.
So the answer is neither.
where [tex]\theta[/tex] is the angle between the vectors. You have
[tex]10\times9+6\times5=\sqrt{10^2+6^2}\sqrt{9^2+5^2}\cos\theta\iff \cos\theta=\dfrac{30}{\sqrt{901}}\implies \theta\approx1.909^\circ[/tex]
The vectors would be orthogonal if the dot product had been zero, but that's clearly not the case.
They would be parallel if the angle turned out to be [tex]0^\circ[/tex] or [tex]180^\circ[/tex], but that's also not the case.
So the answer is neither.