Answer :

Hope008

Answer:

  • [tex]\sf C.\; \sf \left(x-1\right)\left(x^2+x+1\right)[/tex]

Step-by-step explanation:

[tex]\sf x^3-1[/tex]

Let's rewrite 1 as 1 ^3.

[tex]\sf x^3-1^3[/tex]

Now, we can apply the "Difference of Cubes Formula".

[tex]\boxed{\sf x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)}[/tex]

  • [tex]\sf x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)[/tex]
  • [tex]\sf \left(x-1\right)\left(x^2+x+1\right)[/tex]

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