[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:f(x)= 9280 - 20x [/tex]
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[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: \cfrac{1}{16} x + \cfrac{1}{320} y - 29 = 0[/tex]
[tex]\qquad \tt \rightarrow \: \cfrac{1}{16} x + \cfrac{1}{320} y = 29[/tex]
[tex]\qquad \tt \rightarrow \: \cfrac{20 x+ y}{320} = 29[/tex]
[tex]\qquad \tt \rightarrow \: 20x + y = 29 \sdot320[/tex]
[tex]\qquad \tt \rightarrow \: y = 9280 - 20x[/tex]
[tex]\qquad \tt \rightarrow \: f(x) = 9280 - 20x[/tex]
- [tex] \textsf{Correct option - A } [/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
