Answer :
Answer:
[tex]x = \frac{-7 +\sqrt{489} }{2}[/tex]
[tex]x = \frac{-7 - \sqrt{489} }{2}[/tex]
Step-by-step explanation:
2x² +21x-61 = (x+7)²
expand
2x² + 21x - 61 = x² + 14x +49
move everything to one side
x² + 7x - 12 = 0
use quadratic formula
[tex]x = \frac{-b +- \sqrt{b^{2}-4ac } }{2a}[/tex]
plug in the values
[tex]x = \frac{-7 +- \sqrt{7^{2}-4(1)(-110) } }{2(1)}[/tex]
solve
[tex]x = \frac{-7 +- \sqrt{49-4(1)(-110) } }{2}[/tex]
[tex]x = \frac{-7 +- \sqrt{49 + 440 } }{2}[/tex]
[tex]x = \frac{-7 +- \sqrt{489} }{2}[/tex]
after you rewrite the equation, identify the coefficients , substitute the coefficients and simplify the expression you’ll be left with 489