Answered

A sample of neon gas occupies a volume of 414 mL at a pressure of 1.15 atm. What will be the pressure of the gas if the volume is increased to 825 mL

Answer :

Answer:

.577 atm

Explanation:

P1 V1  = P2 V2

RE-ARRANGE TO     P2 = P1 V1 / V2

Sub in the given values

  P2 = 1.15 * .414 / .825 = .577 atm

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