Answer :
It must be noted that during an elastic collision both the momentum and kinetic energy are conserved. For the kinetic energy, it can be solved through the equation,
KE = 0.5mv²
Equating the kinetic energies before and after collision,
0.5(60)(8 m/s)² = (0.5)(60)(x²) + (0.5)(0.45)(35 m/s)²
The value of x from the equation is approximately 7.40 m/s
KE = 0.5mv²
Equating the kinetic energies before and after collision,
0.5(60)(8 m/s)² = (0.5)(60)(x²) + (0.5)(0.45)(35 m/s)²
The value of x from the equation is approximately 7.40 m/s
Answer:
v = 7.73 m/s
Explanation:
It is given that,
Mass of the player, m₁ = 60 kg
Initial speed of the player, u₁ = 8 m/s
Mass of the soccer ball, m₂ = 0.45 kg
Initial speed of the player, u₂ = 0 (at rest)
After the collision,
Final speed of the player, v₁
Final speed of the ball, v₂ = 35 m/s
Using the conservation of linear momentum to find the final speed of the player. Mathematically, it is given by :
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
[tex]m_1u_1=m_1v_1+m_2v_2[/tex]
[tex]60\times 8=60\times v_1+0.45\times 35[/tex]
[tex]v_1=7.73\ m/s[/tex]
So, the speed of the soccer player immediately after kicking the ball is 7.73 m/s. Hence, this is the required solution.