Answer :

The slower one walks at a rate of 2.2 mi/h, and the faster one walks at a rate of 3.3 mi/h

How to find the rate of the hikers?

The given information is the following:

  • The distance between the hikers is 33 miles.
  • They meet in 6 hours.
  • One of them walks 1.1 miles per hour faster than the other.

If we define x as the rate of the slower one and y as the rate of the faster one, then we can write the equation:

(x + y)*6h = 33mi

And now we can write:

y = x + 1.1mi/h

Replacing that we get the linear equation:

(x + x + 1.1mi/h)*6h = 33mi

(2x + 1.1mi/h)*6h = 33mi

(2x + 1.1 mi/h) = 33mi/6h = 5.5mi/h

2x = 5.5mi/h - 1.1mi/h = 4.4mi/h

x = (4.4mi/h)/2 = 2.2 mi/h

The slower one walks at a rate of 2.2 mi/h, and the faster one walks at a rate of 3.3 mi/h.

If you want to learn more about linear equations:

https://brainly.com/question/1884491

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