Answered

At a particular pressure and temperature, nitrogen gas effuses at the rate of 82 ml/s. using the same apparatus at the same temperature and pressure, at what rate will nitrogen dioxide effuse?

Answer :

Eduard22sly

The rate at which the nitrogen dioxide, NO₂ will effuse is 64 mL/s

Graham's law of diffusion

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

Where

  • R₁ and R₂ are the rates of each gas
  • M₁ and M₂ are the molar mass of each gas

How to determine the rate at which nitrogen dioxide, NO₂ will deffuse

  • Rate of N₂ (R₁) = 82 mL/s
  • Molar mass of N₂ (M₁) = 28 g/mol
  • Molar mass of NO₂ (M₂) = 46 g/mol
  • Rate of NO₂ (R₂) =?

Applying the Graham's law of diffusion equation, we have:

R₁/R₂ = √(M₂/M₁)

82 / R₂ = √(46 / 28)

Cross multiply

82 = R₂√(46 / 28)

Divide both sides by √(46 / 28)

R₂ = 82 /√(46 / 28)

R₂ = 64 mL/s

Thus, nitrogen dioxide, NO₂ will effuse at 64 mL/s

Learn more about Graham's law of diffusion:

https://brainly.com/question/14004529

#SPJ4

Other Questions