A spherical hot-air balloon has a diameter of 55 feet. when the balloon is inflated, the radius increases at a rate of 1.5 feet per minute. approximately how long does it take to inflate the balloon to two-thirds of its maximum volume? use π = 3.14 and v = four-thirds pi r cubed. 16 minutes 18 minutes 23 minutes 26 minutes

Answer :

Time taken to inflate the balloon to two-thirds of its maximum volume is 16 minutes.

Given the diameter of the balloon = 55 ft

Let r be the radius of the balloon. Then r = 55/2 = 27.5 ft

Rate of change of radius = 1.5 ft/min.

The maximum volume of the balloon = [tex]\frac{4}{3}\pi r^3[/tex] = [tex]\frac{4}{3}\times3.14\times 27.5^3[/tex]

                                                              = 87069.583 [tex]ft^3[/tex]

Two- thirds of the volume = (2/3) x 87069.583 = 58046.389  [tex]ft^3[/tex]

Let R be the radius of the balloon with two-thirds of its maximum volume.

Then, [tex]\frac{4}{3}\pi R^3[/tex] =  58046.389

⇒          [tex]R^3=\frac{3}{4\times3.14}\times 58046.389[/tex] = 13864.583

⇒            [tex]R=13864.583^\frac{1}{3}[/tex]

⇒           R = 24.023 ft

Now time taken to inflate balloon to the two-third of the maximum volume = 24.023/1.5 = 16 minutes approximately.

Learn more about the Volume of a sphere at https://brainly.com/question/22716418

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