Answer :
Answer:
[tex]1\frac78[/tex] meters tall
Step-by-step explanation:
Hello!
I'm assuming we're solving for the height of Shanika.
Let the height of Shanika be called "s".
Equation: [tex]\frac32 = \frac45s[/tex]
Solve for s
- [tex]\frac32 = \frac45s[/tex]
- [tex]$\frac{\frac32}{\frac45} = s[/tex]
- [tex]\frac32 \div \frac45 = s[/tex]
- [tex]\frac{3*5}{2*4} = s[/tex]
- [tex]\frac{15}{8} = s[/tex]
- [tex]1 \frac78 = s[/tex]
Shanika is [tex]1\frac78[/tex] meters tall.