Answered

A bag contains 10 red, 5 yellow, and 6 blue marbles. What is the probability of pulling out one blue marble and then one red marble without replacing the first blue marble?

Answer :

MrRoyal

The probability of pulling out one blue marble and then one red marble without replacing the first blue marble is 1/7

How to determine the probability?

The given parameters are

Red = 10

Yellow = 5

Blue = 6

The probability of pulling out one blue marble and then one red marble without replacing the first blue marble is

P = P(Blue) * P(Red Having selected Blue)

So, we have

P = 6/21 * 10/20

Evaluate

P = 1/7

Hence, the probability of pulling out one blue marble and then one red marble without replacing the first blue marble is 1/7

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