Answer :
By using Hooke's Law, the work done is 400 joule.
We need to know about Hooke's Law to solve this problem. Hooke's Law describes the force applied to spring (elastic materials) will proportional to spring constant and displacement under the elastic condition. It can be described as
F = k . x
where F is force, k is spring constant and x is displacement.
The potential energy of spring can be determined as
PE = 1/2 . k . x²
where PE is potential energy
From the question above, we know that
PE1 = 100 J
x1 = 1 m
x2 = x1 + 1 m = 2 m
Potential energy is proportional to squared displacement, the ratio of PE can be written as
PE1 / PE2 = x1² / x2²
100 / PE2 = 1² / 2²
PE2 = 400 joule
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