The final speed of the ball can be given as,
[tex]v^2=u^2-2gh[/tex]At the maximum height the final speed is zero.
Plug in the known values,
[tex]\begin{gathered} (0m/s)^2=u^2-2(9.8m/s^2)(57.0\text{ m)} \\ u^2=2(9.8m/s^2)(57.0\text{ m)} \\ u=\sqrt[]{1117.2m^2s^{-2}} \\ =33.4\text{ m/s} \end{gathered}[/tex]Therefore, the speed with which the ball was kicked is 33.4 m/s.
Also, the final speed of the ball can be expressed as,
[tex]v=u-gt[/tex]Plug in the known values,
[tex]\begin{gathered} 0m/s=33.4m/s-(9.8m/s^2)t \\ t=\frac{33.4\text{ m/s}}{9.8m/s^2} \\ \approx3.41\text{ s} \end{gathered}[/tex]The total time flight time of the ball is calculated as,
[tex]undefined[/tex]Therefore, the total flight time of the ball is 3.41 s.