Step 1
From the image;
[tex]Triangle\text{ ABE\textasciitilde Triangle ACD}[/tex][tex]\begin{gathered} Find\text{ the value of x to know if the sides are proportional} \\ \frac{12}{8}=\frac{6+x}{x} \\ 12x=48+8x \\ 4x=48 \\ x=\frac{48}{4}=12 \end{gathered}[/tex]Hence;
[tex]\begin{gathered} \frac{12+6}{12}=\frac{8+4}{8} \\ \frac{18}{12}=\frac{12}{8} \\ \frac{3}{2}=\frac{3}{2} \end{gathered}[/tex]The triangles also share similar angles therefore the answer will be;
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