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The table below shows the students in an Algebra class.GirlsBoysTotalOwn a graphing Do not own a graphingcalculatorcalculator125176713Total181230What is the probability that a randomly chosen student will be a girl and own a graphingcalculator?

The table below shows the students in an Algebra class.GirlsBoysTotalOwn a graphing Do not own a graphingcalculatorcalculator125176713Total181230What is the pro class=

Answer :

Explanation:

The total number of students in the algebra class is given below as

[tex]n(S)=30[/tex]

The number of girsl who won a graphing calculator is given below as

[tex]\begin{gathered} n(G_h\cap G_n)=12 \\ where, \\ G_h=have\text{ }graphing\text{ }calculator \\ G_n=does\text{ }not\text{ }have\text{ }graphing \end{gathered}[/tex]

Concept:

To figure out the probabaility that a randomly chosen student will be a girl and own a graphing calculator, we will use the formula below

[tex]Pr(G_h\cap G_n)=\frac{n(G_h\cap G_n)}{n(S)}[/tex]

By substituting the values, we will have

[tex]\begin{gathered} Pr(G_{h}\operatorname{\cap}G_{n})=\frac{n(G_{h}\operatorname{\cap}G_{n})}{n(S)} \\ Pr(G_h\operatorname{\cap}G_n)=\frac{12}{30} \\ Pr(G_h\operatorname{\cap}G_n)=\frac{2}{5} \end{gathered}[/tex]

Hence,

The final answer is

[tex]\frac{2}{5}[/tex]

The FOUTH OPTION is the correct answer

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