Answer :
Solution
Let x=cost of hotdog
Let y=cost of hamburger ;
7x+4y=$14.00 ................(1)
4x+7y=$16.25 .................(2)
7x+4y=$14.00 Multiply this equation by 4
4x+7y=$16.25 Multiply this equation by 7
[tex]\begin{gathered} 28x+16y=56 \\ \frac{28x+49y=113.75}{-33y=-57.75} \\ y=-\frac{57.75}{=33} \\ y=1.75 \end{gathered}[/tex]sub the value of y in equ(1)
[tex]\begin{gathered} 7x+4y=14 \\ 7x+4(1.75)=14 \\ 7x+7=14 \\ 7x=14-7 \\ 7x=7 \\ x=\frac{7}{7} \\ x=1 \end{gathered}[/tex]Therefore the cost of one hotdog = $1 , and the cost of one hamburger = $1.75